WebSee Answer Question: Consider the equilibrium reaction. 2A+B↽−−⇀4C2A+B↽−−⇀4C After multiplying the reaction by a factor of 2,2, what is the new equilibrium equation? new equilibrium equation: 4A+2B↽−−⇀8C4A+2B↽−−⇀8C Create the equilibrium‑constant expression, 𝐾c,Kc, for the new equilibrium reaction. 𝐾c=Kc= [C]4 [C]4 [A]2 [A]2 [B] [B] Answer WebMar 11, 2024 · Answer: 6a×2b×2-4ab / a=2, b=-1 6×2 × 2×-1 ×2 -4×2×-1 12×-2×2 - (-8) 12×-4+8 -48+8 -40 Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions NCERT Class 8 Mathematics 815 solutions NCERT Class 7 Mathematics 916 solutions NCERT Class 10 …
Evaluate. (a−2b)³ when a=−4 and b=−1/2 Enter your
WebNov 14, 2024 · (2ab - b 2) : (6a 2 - ab) = 1 : 6. ⇒ 6 × (2ab - b 2) = 1 × (6a 2 - ab) ⇒ 12ab - 6b 2 = 6a 2 - ab. ⇒ 6a 2 - 13ab + 6b 2 = 0. ⇒ 6a 2 - 9ab - 4ab + 6b 2 = 0. ⇒ 3a (2a - 3b) - 2b (2a - … WebSo this expression would be equal to 9 in this circumstance. Let's do a slightly more complicated one. Let's say we have the expression x times y minus y plus x. Actually, let's make it plus 3x. Or another way of saying it plus 3 times x. So let's evaluate this when x is equal to 3 and y is equal to 2. state of basti
Evaluating expressions with two variables - Khan Academy
Webfactor quadratic x^2-7x+12; expand polynomial (x-3)(x^3+5x-2) GCD of x^4+2x^3-9x^2+46x-16 with x^4-8x^3+25x^2-46x+16; quotient of x^3-8x^2+17x-6 with x-3; remainder of x^3-2x^2+5x-7 divided by x-3; roots of x^2-3x+2; View more examples » Access instant learning tools. Get immediate feedback and guidance with step-by-step solutions and Wolfram ... WebAug 5, 2024 · The exponent of b is 2. The sum of the exponents, 1+2,1+2, is 3 so the degree is 3. Here are some additional examples. Working with polynomials is easier when you list the terms in descending order of degrees. When a polynomial is written this way, it is said to be in standard form of a polynomial. WebFeb 8, 2024 · 14a = 8b. 7a = 4b or, a = 4b/7. Now, by substituting a, we get the value of the equation as 11. sufficient. 2) 6a - 3b = 3 or, 2a - b =1 or, b = 2a. if we substitute b in the … state of bastar